MSSQL 获取递归树形表数据
发布时间:2023-05-09 13:12:51 所属栏目:MsSql教程 来源:
导读:根据节点主键,查询当前节点和所有子节点
WITH SOURCE AS (
SELECT * FROM TableName WHERE DeleteState = 0
),
LIST AS (
SELECT value FROM STRING_SPLIT('2111011043240001', ',')
)
WITH SOURCE AS (
SELECT * FROM TableName WHERE DeleteState = 0
),
LIST AS (
SELECT value FROM STRING_SPLIT('2111011043240001', ',')
)
根据节点主键,查询当前节点和所有子节点 WITH SOURCE AS ( SELECT * FROM TableName WHERE DeleteState = 0 ), LIST AS ( SELECT value FROM STRING_SPLIT('2111011043240001', ',') ), RESULT AS ( SELECT SOURCE.* FROM SOURCE INNER JOIN LIST ON SOURCE.Code = LIST.value UNION ALL SELECT SOURCE.* FROM RESULT INNER JOIN SOURCE ON RESULT.Code = SOURCE.ParentCode ) SELECT Code, ParentCode, NodeName, NodeIndex, IsLastNode FROM RESULT (编辑:汽车网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
推荐文章
站长推荐