PHP实现求两个字符串最长公共子串的技巧示例
发布时间:2023-10-06 11:47:28 所属栏目:PHP教程 来源:
导读:代码如下:
<?php
$a = 'abceee12345309878';
$b = 'abceeew2345i09878fsfsfsfabceeewsfsdfsfsabceeew';
$c = array();
$lenht1 = strlen($a);
$lenth2 = strlen($b);
$startTime =
<?php
$a = 'abceee12345309878';
$b = 'abceeew2345i09878fsfsfsfabceeewsfsdfsfsabceeew';
$c = array();
$lenht1 = strlen($a);
$lenth2 = strlen($b);
$startTime =
代码如下: <?php $a = 'abceee12345309878'; $b = 'abceeew2345i09878fsfsfsfabceeewsfsdfsfsabceeew'; $c = array(); $lenht1 = strlen($a); $lenth2 = strlen($b); $startTime = microtime(true); for ($i=0;$i<$lenht1;$i++) { for ($j=0;$j<$lenth2;$j++) { $n = ($i-1>=0 && $j-1>=0)?$c[$i-1][$j-1]:0; $n = ($a[$i] == $b[$j]) ? $n+1:0; $c[$i][$j] = $n; } } foreach ($c as $key=>$val) { $max = max($val); foreach ($val as $key1 =>$val1) { if ($val1 == $max && $max>0) { $cdStr[$max] = substr($b,$key1-$max+1,$max); } //Cuoxin.com } } ksort($cdStr); $endTime = microtime(true); echo "Totle time is " . ($endTime - $startTime) . " s"."<br/>"; print_r(end($cdStr)); exit; ?> 运行结果: Totle time is 0.0012800693512 s abceee (编辑:汽车网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
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